Joule to Foot-pound Converter
1 J = 0.737562 ft·lbf
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FORMULA
1 J = 0.737562 ft·lbf
CONVERSION TABLE
| Joule (J) | Foot-pound (ft·lbf) |
|---|---|
| 1 J | 0.737562 ft·lbf |
| 5 J | 3.6878 ft·lbf |
| 10 J | 7.3756 ft·lbf |
| 25 J | 18.4391 ft·lbf |
| 50 J | 36.8781 ft·lbf |
| 100 J | 73.7562 ft·lbf |
| 250 J | 184.3905 ft·lbf |
| 500 J | 368.7811 ft·lbf |
| 1,000 J | 737.5621 ft·lbf |
COMMON VALUES
RELATED CONVERSIONS
About Joule (J)
The SI derived unit of energy, one joule equals the work done by a force of one newton moving an object one meter. Named after James Prescott Joule, who demonstrated the mechanical equivalent of heat, the joule is used in physics, chemistry, and engineering for all forms of energy, work, and heat.
About Foot-pound (ft·lbf)
The energy exerted by a force of one pound-force through a displacement of one foot, equal to approximately 1.356 joules. Torque wrenches for automotive work are calibrated in foot-pounds, and bullet muzzle energies are commonly listed in foot-pounds to help shooters compare cartridge power.
How to Convert Joule to Foot-pound
The conversion formula is: 1 J = 0.737562 ft·lbf. To convert from Joule (J) to Foot-pound (ft·lbf), use the formula above or the interactive converter at the top of this page.
Frequently Asked Questions
How many Foot-pound in 1 Joule?
1 Joule (J) equals 0.737562 Foot-pound (ft·lbf).
How to convert Joule to Foot-pound?
Multiply the Joule value by 0.737562 to get the equivalent in Foot-pound. Formula: 1 J = 0.737562 ft·lbf
What is the formula for Joule to Foot-pound conversion?
1 J = 0.737562 ft·lbf
Glossary
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Calorie
A unit of energy. The small calorie (cal) heats 1g of water by 1°C; the food Calorie (kcal) is 1000 small calories.
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BTU (British Thermal Unit)
The amount of heat needed to raise the temperature of one pound of water by one degree Fahrenheit.
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Electronvolt
A unit of energy equal to the kinetic energy gained by an electron accelerated through 1 volt.
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Joule
The SI unit of energy, equal to the work done by a force of one newton acting over a distance of one meter (1 J = 1 N·m = 1 kg·m²/s²).