Foot-pound Force to Newton-meter Converter
1 ft·lbf = 1.3558 N·m
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FORMULA
1 ft·lbf = 1.3558 N·m
CONVERSION TABLE
| Foot-pound Force (ft·lbf) | Newton-meter (N·m) |
|---|---|
| 1 ft·lbf | 1.3558 N·m |
| 5 ft·lbf | 6.7791 N·m |
| 10 ft·lbf | 13.5582 N·m |
| 25 ft·lbf | 33.8954 N·m |
| 50 ft·lbf | 67.7909 N·m |
| 100 ft·lbf | 135.5818 N·m |
| 250 ft·lbf | 338.9545 N·m |
| 500 ft·lbf | 677.909 N·m |
| 1,000 ft·lbf | 1,355.82 N·m |
COMMON VALUES
RELATED CONVERSIONS
About Foot-pound Force (ft·lbf)
The standard torque unit in US automotive and mechanical work, one foot-pound equals approximately 1.356 Nm. Torque wrenches are calibrated in ft-lbf, lug nut specifications (typically 80-100 ft-lbf for passenger cars), and engine torque figures in US-market vehicles use this unit.
About Newton-meter (N·m)
The SI derived unit of torque, one newton-meter is the torque produced by a force of one newton applied at a one-meter lever arm. Automotive engine specifications list peak torque in Nm (a family sedan produces 200-350 Nm), and bolt tightening specifications in maintenance manuals use newton-meters.
How to Convert Foot-pound Force to Newton-meter
The conversion formula is: 1 ft·lbf = 1.3558 N·m. To convert from Foot-pound Force (ft·lbf) to Newton-meter (N·m), use the formula above or the interactive converter at the top of this page.
Frequently Asked Questions
How many Newton-meter in 1 Foot-pound Force?
1 Foot-pound Force (ft·lbf) equals 1.3558 Newton-meter (N·m).
How to convert Foot-pound Force to Newton-meter?
Multiply the Foot-pound Force value by 1.3558 to get the equivalent in Newton-meter. Formula: 1 ft·lbf = 1.3558 N·m
What is the formula for Foot-pound Force to Newton-meter conversion?
1 ft·lbf = 1.3558 N·m