Newton-meter to Foot-pound Force Converter
1 N·m = 0.737562 ft·lbf
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FORMULA
1 N·m = 0.737562 ft·lbf
CONVERSION TABLE
| Newton-meter (N·m) | Foot-pound Force (ft·lbf) |
|---|---|
| 1 N·m | 0.737562 ft·lbf |
| 5 N·m | 3.6878 ft·lbf |
| 10 N·m | 7.3756 ft·lbf |
| 25 N·m | 18.4391 ft·lbf |
| 50 N·m | 36.8781 ft·lbf |
| 100 N·m | 73.7562 ft·lbf |
| 250 N·m | 184.3905 ft·lbf |
| 500 N·m | 368.7811 ft·lbf |
| 1,000 N·m | 737.5621 ft·lbf |
COMMON VALUES
RELATED CONVERSIONS
About Newton-meter (N·m)
The SI derived unit of torque, one newton-meter is the torque produced by a force of one newton applied at a one-meter lever arm. Automotive engine specifications list peak torque in Nm (a family sedan produces 200-350 Nm), and bolt tightening specifications in maintenance manuals use newton-meters.
About Foot-pound Force (ft·lbf)
The standard torque unit in US automotive and mechanical work, one foot-pound equals approximately 1.356 Nm. Torque wrenches are calibrated in ft-lbf, lug nut specifications (typically 80-100 ft-lbf for passenger cars), and engine torque figures in US-market vehicles use this unit.
How to Convert Newton-meter to Foot-pound Force
The conversion formula is: 1 N·m = 0.737562 ft·lbf. To convert from Newton-meter (N·m) to Foot-pound Force (ft·lbf), use the formula above or the interactive converter at the top of this page.
Frequently Asked Questions
How many Foot-pound Force in 1 Newton-meter?
1 Newton-meter (N·m) equals 0.737562 Foot-pound Force (ft·lbf).
How to convert Newton-meter to Foot-pound Force?
Multiply the Newton-meter value by 0.737562 to get the equivalent in Foot-pound Force. Formula: 1 N·m = 0.737562 ft·lbf
What is the formula for Newton-meter to Foot-pound Force conversion?
1 N·m = 0.737562 ft·lbf